Optimal. Leaf size=298 \[ -\frac{i c \sqrt{a^2 x^2+1} \text{PolyLog}\left (2,-\frac{i \sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{8 a^3 \sqrt{a^2 c x^2+c}}+\frac{i c \sqrt{a^2 x^2+1} \text{PolyLog}\left (2,\frac{i \sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{8 a^3 \sqrt{a^2 c x^2+c}}-\frac{\left (a^2 c x^2+c\right )^{3/2}}{12 a^3 c}+\frac{\sqrt{a^2 c x^2+c}}{8 a^3}+\frac{1}{4} x^3 \sqrt{a^2 c x^2+c} \tan ^{-1}(a x)+\frac{x \sqrt{a^2 c x^2+c} \tan ^{-1}(a x)}{8 a^2}+\frac{i c \sqrt{a^2 x^2+1} \tan ^{-1}(a x) \tan ^{-1}\left (\frac{\sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{4 a^3 \sqrt{a^2 c x^2+c}} \]
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Rubi [A] time = 0.269668, antiderivative size = 298, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.318, Rules used = {4946, 4952, 261, 4890, 4886, 266, 43} \[ -\frac{i c \sqrt{a^2 x^2+1} \text{PolyLog}\left (2,-\frac{i \sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{8 a^3 \sqrt{a^2 c x^2+c}}+\frac{i c \sqrt{a^2 x^2+1} \text{PolyLog}\left (2,\frac{i \sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{8 a^3 \sqrt{a^2 c x^2+c}}-\frac{\left (a^2 c x^2+c\right )^{3/2}}{12 a^3 c}+\frac{\sqrt{a^2 c x^2+c}}{8 a^3}+\frac{1}{4} x^3 \sqrt{a^2 c x^2+c} \tan ^{-1}(a x)+\frac{x \sqrt{a^2 c x^2+c} \tan ^{-1}(a x)}{8 a^2}+\frac{i c \sqrt{a^2 x^2+1} \tan ^{-1}(a x) \tan ^{-1}\left (\frac{\sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{4 a^3 \sqrt{a^2 c x^2+c}} \]
Antiderivative was successfully verified.
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Rule 4946
Rule 4952
Rule 261
Rule 4890
Rule 4886
Rule 266
Rule 43
Rubi steps
\begin{align*} \int x^2 \sqrt{c+a^2 c x^2} \tan ^{-1}(a x) \, dx &=\frac{1}{4} x^3 \sqrt{c+a^2 c x^2} \tan ^{-1}(a x)+\frac{1}{4} c \int \frac{x^2 \tan ^{-1}(a x)}{\sqrt{c+a^2 c x^2}} \, dx-\frac{1}{4} (a c) \int \frac{x^3}{\sqrt{c+a^2 c x^2}} \, dx\\ &=\frac{x \sqrt{c+a^2 c x^2} \tan ^{-1}(a x)}{8 a^2}+\frac{1}{4} x^3 \sqrt{c+a^2 c x^2} \tan ^{-1}(a x)-\frac{c \int \frac{\tan ^{-1}(a x)}{\sqrt{c+a^2 c x^2}} \, dx}{8 a^2}-\frac{c \int \frac{x}{\sqrt{c+a^2 c x^2}} \, dx}{8 a}-\frac{1}{8} (a c) \operatorname{Subst}\left (\int \frac{x}{\sqrt{c+a^2 c x}} \, dx,x,x^2\right )\\ &=-\frac{\sqrt{c+a^2 c x^2}}{8 a^3}+\frac{x \sqrt{c+a^2 c x^2} \tan ^{-1}(a x)}{8 a^2}+\frac{1}{4} x^3 \sqrt{c+a^2 c x^2} \tan ^{-1}(a x)-\frac{1}{8} (a c) \operatorname{Subst}\left (\int \left (-\frac{1}{a^2 \sqrt{c+a^2 c x}}+\frac{\sqrt{c+a^2 c x}}{a^2 c}\right ) \, dx,x,x^2\right )-\frac{\left (c \sqrt{1+a^2 x^2}\right ) \int \frac{\tan ^{-1}(a x)}{\sqrt{1+a^2 x^2}} \, dx}{8 a^2 \sqrt{c+a^2 c x^2}}\\ &=\frac{\sqrt{c+a^2 c x^2}}{8 a^3}-\frac{\left (c+a^2 c x^2\right )^{3/2}}{12 a^3 c}+\frac{x \sqrt{c+a^2 c x^2} \tan ^{-1}(a x)}{8 a^2}+\frac{1}{4} x^3 \sqrt{c+a^2 c x^2} \tan ^{-1}(a x)+\frac{i c \sqrt{1+a^2 x^2} \tan ^{-1}(a x) \tan ^{-1}\left (\frac{\sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{4 a^3 \sqrt{c+a^2 c x^2}}-\frac{i c \sqrt{1+a^2 x^2} \text{Li}_2\left (-\frac{i \sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{8 a^3 \sqrt{c+a^2 c x^2}}+\frac{i c \sqrt{1+a^2 x^2} \text{Li}_2\left (\frac{i \sqrt{1+i a x}}{\sqrt{1-i a x}}\right )}{8 a^3 \sqrt{c+a^2 c x^2}}\\ \end{align*}
Mathematica [A] time = 2.83128, size = 278, normalized size = 0.93 \[ \frac{\sqrt{c \left (a^2 x^2+1\right )} \left (-6 i \text{PolyLog}\left (2,-i e^{i \tan ^{-1}(a x)}\right )+6 i \text{PolyLog}\left (2,i e^{i \tan ^{-1}(a x)}\right )-\frac{1}{4} \left (a^2 x^2+1\right )^2 \left (-\frac{2}{\sqrt{a^2 x^2+1}}+3 \tan ^{-1}(a x) \left (-\frac{14 a x}{\sqrt{a^2 x^2+1}}+3 \log \left (1-i e^{i \tan ^{-1}(a x)}\right )-3 \log \left (1+i e^{i \tan ^{-1}(a x)}\right )+2 \sin \left (3 \tan ^{-1}(a x)\right )+4 \left (\log \left (1-i e^{i \tan ^{-1}(a x)}\right )-\log \left (1+i e^{i \tan ^{-1}(a x)}\right )\right ) \cos \left (2 \tan ^{-1}(a x)\right )+\left (\log \left (1-i e^{i \tan ^{-1}(a x)}\right )-\log \left (1+i e^{i \tan ^{-1}(a x)}\right )\right ) \cos \left (4 \tan ^{-1}(a x)\right )\right )-6 \cos \left (3 \tan ^{-1}(a x)\right )\right )\right )}{48 a^3 \sqrt{a^2 x^2+1}} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.559, size = 199, normalized size = 0.7 \begin{align*}{\frac{6\,\arctan \left ( ax \right ){x}^{3}{a}^{3}-2\,{a}^{2}{x}^{2}+3\,\arctan \left ( ax \right ) xa+1}{24\,{a}^{3}}\sqrt{c \left ( ax-i \right ) \left ( ax+i \right ) }}+{\frac{1}{8\,{a}^{3}}\sqrt{c \left ( ax-i \right ) \left ( ax+i \right ) } \left ( \arctan \left ( ax \right ) \ln \left ( 1+{i \left ( 1+iax \right ){\frac{1}{\sqrt{{a}^{2}{x}^{2}+1}}}} \right ) -\arctan \left ( ax \right ) \ln \left ( 1-{i \left ( 1+iax \right ){\frac{1}{\sqrt{{a}^{2}{x}^{2}+1}}}} \right ) -i{\it dilog} \left ( 1+{i \left ( 1+iax \right ){\frac{1}{\sqrt{{a}^{2}{x}^{2}+1}}}} \right ) +i{\it dilog} \left ( 1-{i \left ( 1+iax \right ){\frac{1}{\sqrt{{a}^{2}{x}^{2}+1}}}} \right ) \right ){\frac{1}{\sqrt{{a}^{2}{x}^{2}+1}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\sqrt{a^{2} c x^{2} + c} x^{2} \arctan \left (a x\right ), x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{2} \sqrt{c \left (a^{2} x^{2} + 1\right )} \operatorname{atan}{\left (a x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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